JEE Main Normalising Process For Class XII Marks
All the students who are appeared in the JEE Main 2013 are hereby informed that the results was announced yesterday. These results are used to decide the eligibility of a student to appear in JEE (Advanced). All the students who wrote the JEE Main 2013 can check its merit calculation details here.
The officials announced that JEE Advanced will be held on June 2. Final merit list for JEE Mains will be published in July after results of all 29 school boards, including the CBSE, are declared. From this year, all technical institutions, except IITs, will give weightage of 60 pc to JEE Mains scores and 40 pc to school marks for preparing merit of all 12,00,000 JEE Main candidates.
Merit Calculation Process :
Step 1: Suppose you score 310 out of 360 in JEE Mains and your percentile is 90. Your JEE Mains contribution to aggregate score will be 310 multiplied by 0.6 (60 pc) equals 186
Step 2: Suppose your school board score is 620 out of 1000 in West Bengal Board. These marks will be converted into percentile which is say 74.
Step 3: JEE Main score list will be scanned to see what marks correspond to 74 percentile you got in school. Suppose those marks are 265. These will be multiplied by 0.2 (half of 40 pc weightage) to yield 53 marks
Step 4: Computer will again use your school percentile to see how many are representative of that percentile in JEE Mains score list but this time it will only see marks for 74 percentile attained by JEE Main candidates from West Bengal. Suppose that score is 200. This will be multiplied with 0.2 (remaining weightage for 40 pc school marks) to yield 40 marks.
Step 5: Marks from Step 1, 3 and 4 will be added to calculate aggregate score. JEE merit list will thus be prepared.
Step 6: Three tables will help in calculations – marks to percentile table for each of 29 boards; Marks to percentile table for JEE scores; marks to percentile table for JEE scorers from each of the 29 boards
Click here for : JEE Main 2013 Merit calculation
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